Question

What is the concentration of HNO3 if 4.60×10−2 mol are present in 895 mL of the solution? Express your answer with the appropriate units.

Answer 1

The concentration of HNO3 in the solution is 0.0514 M, which is the result of dividing the number of moles (4.60×10⁻² mol) by the volume in liters (0.895 L).

Step-by-step explanation:

To calculate the concentration of HNO3 in the solution, we need to divide the number of moles of HNO3 by the volume of the solution expressed in liters. The number of moles given is 4.60×10⁻² mol, and the volume provided is 895 mL, which is 0.895 L when converted. Therefore, the concentration of HNO3 is:

Concentration of HNO3 = (Number of moles)/(Volume in liters)

Concentration of HNO3 = (4.60×10⁻² mol) / (0.895 L)

Concentration of HNO3 = 0.0514 M (molarity)