Final answer:
The height from which the body started falling and the total time of motion in free fall can be found using kinematic equations and the provided information about the distance covered in the last 2 seconds of fall.
Step-by-step explanation:
To determine the height from which the body was released and the total time of motion during its free fall, we can use the kinematic equations for uniformly accelerated motion, where the acceleration is due to gravity (g=10 m/s2). We are given that the body covered 100 m during the last 2 seconds of its fall. Using the equation for the distance covered during the nth second, which is given by dn = u + (1/2)g(2n-1), where dn is the distance covered during the nth second, u is the initial velocity at the beginning of nth second, g is the acceleration due to gravity, and n is the time in seconds, we can find the initial velocity (u) just before the last 2 seconds.
Let's consider the body was in free fall for t seconds, so the last 2 seconds would be t and t-1, respectively. For these 2 seconds, we have:
- The distance covered during the second-to-last second (dt-1) = u + (1/2)g(2(t-1)-1)
- The distance covered during the last second (dt) = u + (1/2)g(2t-1)
Since the total distance covered in these 2 seconds is 100 m, we have:
- dt-1 + dt = 100 m
- (u + (1/2)g(2(t-1)-1)) + (u + (1/2)g(2t-1)) = 100 m
By solving the above equation, we can find the value of u and then use the equation of motion s = ut + (1/2)gt2, where s is the total height, to determine the height from which the body was released and the total time of motion.