Final answer:
Increasing the concentration of isopropanol from 2 w/w% to 15 w/w% leads to a more concentrated solution of isopropanol molecules with altered physical properties such as boiling point, freezing point, viscosity, and density.
Step-by-step explanation:
When the concentration of isopropanol, C3H7OH, is increased from 2 w/w% to 15 w/w%, the solution becomes more concentrated with the isopropanol molecules. Given that isopropanol, with the formula (CH3)2CHOH, is a nonelectrolyte and dissolves in water to yield a solution of neutral molecules, the outcome involves an increase in concentration of these (CH3)2CHOH molecules. It's important to note that the physical properties of the solution will also change; the boiling and freezing points will differ from those of a more dilute solution, and if the solution is used as a solvent, its solvency power will increase. As the concentration increases, the solution may also exhibit changes in viscosity and density.