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If 14.5 mol of an ideal gas occupies 58.5 L at 67.00 °C, what is the pressure of the gas?

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Final answer:

To find the pressure of the gas, we can use the ideal gas law equation: PV = nRT. Plugging in the given values, the pressure of the gas is 4.51 atm.

Step-by-step explanation:

The question asks for the pressure of the gas. To find the pressure, we can use the ideal gas law equation: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Rearranging the equation to solve for pressure, we have P = (nRT)/V.

Given in the question, the volume of the gas is 58.5 L and the number of moles is 14.5 mol. The gas constant, R, is 0.0821 L·atm/(mol·K). We also need to convert the temperature from Celsius to Kelvin, which is done by adding 273.15 to the Celsius temperature. So, 67.00 °C + 273.15 = 340.15 K.

Plugging in the values into the formula, we get P = (14.5 mol * 0.0821 L·atm/(mol·K) * 340.15 K) / 58.5 L = 4.51 atm.

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