Final answer:
The bond between nitrogen and fluorine is polar covalent with an electronegativity difference of 1.0, and based on information provided, it is inferred to have less than 50% ionic character; without specific data, the exact percent cannot be calculated.
Step-by-step explanation:
To determine the percent ionic character between nitrogen and fluorine, we first need to look at the difference in their electronegativities. Nitrogen has an electronegativity of 3.0, while fluorine has an electronegativity of 4.0. This gives us a difference of 1.0. Referring to the data provided, diatomic species with an electronegativity difference of less than 1.5 are typically less than 50% ionic in character. Since nitrogen and fluorine have a difference of 1.0, which is less than 1.5, we can infer that the bond between them would be considered to have polar covalent character rather than being predominantly ionic. However, without specific dipole moment and bond distance data, we cannot calculate the exact percent ionic character of the nitrogen-fluorine bond.