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An electron with kinetic energy (KE) of 24.5 cV moves into a region of uniform magnetic field B of magnitude 4.45 x 10 5 T. The angle between the direction of B and the electron’s velocity =(cp) is 65.5°. What is the pitch p of the helical path taken by the electron (the pitchp is the distance travelled by the electron parallel to the magnetic field B during one period T of circulation)

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Final answer:

The pitch p of the helical path taken by an electron can be calculated using the formula p = (v * T * sinθ) / B, with the given values substituted into the formula.

Step-by-step explanation:

The pitch p of the helical path taken by an electron can be calculated using the formula p = (v * T * sinθ) / B, where v is the velocity of the electron, T is the period of circulation, θ is the angle between the direction of the magnetic field and the electron's velocity, and B is the magnitude of the magnetic field.

Using the given values, we can substitute v = 24.5 cV, T = 2π/magnetic frequency, and B = 4.45 x 10^5 T into the formula to find the value of p.

An electron moving through a uniform magnetic field, causing it to travel in a helical path. To calculate the pitch of the helix, which is the displacement parallel to the magnetic field B in one period, we would need to know the velocity of the electron and the component of this velocity that is parallel to the magnetic field.

Since the kinetic energy (KE) of the electron is provided, we can use this to find the speed of the electron. The kinetic energy (in electron volts) can be converted to joules, and then using the relation KE = 1/2 mv2, the speed v can be calculated. Once the velocity is known, we can resolve it into components parallel and perpendicular to the magnetic field. The pitch p is then given by the parallel component of the velocity times the period of the circular motion (v|| × T).

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