Final answer:
The temperature change of 2.00-kg water when 505 J of thermal energy is added to it is approximately 0.0604 °C.
Step-by-step explanation:
The temperature change of 2.00 kg of water can be calculated using the specific heat capacity formula:
ΔQ = mcΔT
Where:
- ΔQ is the change in thermal energy, which is given as 505 J
- m is the mass of the water, which is 2.00 kg
- c is the specific heat capacity of water, which is 4.184 J/g °C or 4184 J/kg °C
- ΔT is the change in temperature, which we need to calculate
Substituting the given values into the formula:
505 J = (2.00 kg)(4184 J/kg °C)(ΔT)
Solving for ΔT:
ΔT = 505 J / (2.00 kg * 4184 J/kg °C)
ΔT = 0.0604 °C