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Over the last 4 seconds, a snail has traveled StartFraction 4 Over 9 EndFraction of an inch. If the snail traveled the same distance each second, how far did it travel each second?

User Amaca
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Final answer:

The snail traveled 1/9 of an inch each second. This was found by dividing the total distance (4/9 of an inch) by the total time (4 seconds).

Step-by-step explanation:

The question asks to find out how far a snail traveled each second when it covered StartFraction 4 Over 9 EndFraction of an inch over the last 4 seconds while moving at a constant speed. To solve this, we need to divide the total distance traveled by the total time taken.

The snail traveled StartFraction 4 Over 9 EndFraction of an inch in 4 seconds, so each second it traveled:

Distance per second = Total distance ÷ Total time

Distance per second = (4/9) inch ÷ 4 seconds = StartFraction 4 Over 9 EndFraction of an inch × StartFraction 1 Over 4 EndFraction seconds = StartFraction 1 Over 9 EndFraction of an inch per second.

So, the snail traveled 1/9 of an inch each second.

User Egor Litvinchuk
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