59.3k views
1 vote
5 points

Daelynn received a Christmas bonus from her boss. She can
bring three of her five friends to the restaurant for a special
dinner. Her choice is a *.
.

User David Choi
by
8.8k points

1 Answer

6 votes

Final answer:

Daelynn's choice of bringing three out of her five friends to a restaurant for a special dinner is a mathematical problem involving combinations. There are 10 different combinations of friends she can invite.

Step-by-step explanation:

The student's question involves making a combination which is a mathematical concept where you need to choose a subset of items from a larger set without regard to the order of selection. In this scenario, Daelynn has the option to bring three of her five friends to the restaurant for a special dinner. To determine the number of different groups of three friends she can choose from her five friends, we use the combination formula:

C(n, k) = n! / (k! * (n-k)!),

where n is the total number of items, k is the number of items to choose, and ! denotes factorial. For Daelynn's situation:

C(5, 3) = 5! / (3! * (5-3)!) = (5 * 4 * 3!)/(3! * 2!) = 10

Therefore, Daelynn has 10 different combinations of friends she can invite to dinner.

User MillerMedia
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.