Final answer:
Daelynn's choice of bringing three out of her five friends to a restaurant for a special dinner is a mathematical problem involving combinations. There are 10 different combinations of friends she can invite.
Step-by-step explanation:
The student's question involves making a combination which is a mathematical concept where you need to choose a subset of items from a larger set without regard to the order of selection. In this scenario, Daelynn has the option to bring three of her five friends to the restaurant for a special dinner. To determine the number of different groups of three friends she can choose from her five friends, we use the combination formula:
C(n, k) = n! / (k! * (n-k)!),
where n is the total number of items, k is the number of items to choose, and ! denotes factorial. For Daelynn's situation:
C(5, 3) = 5! / (3! * (5-3)!) = (5 * 4 * 3!)/(3! * 2!) = 10
Therefore, Daelynn has 10 different combinations of friends she can invite to dinner.