Question

How much heat is needed to raise the temperature of an empty 20 kg vat made of iron from 10°C to 90°C? The specific heat of iron is 450 J/kg.C°.

Answer 1

The heat required to raise the temperature of a 20 kg iron vat from 10°C to 90°C is 720,000 Joules, calculated using the specific heat capacity formula.

Step-by-step explanation:

To calculate the amount of heat needed to raise the temperature of a 20 kg iron vat from 10°C to 90°C, you can use the specific heat formula: q = mcΔT, where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Using the provided values:

• Mass, m = 20,000 g (since 1 kg = 1,000 g)
• Specific heat capacity of iron, c = 0.450 J/g°C (same as given 450 J/kg°C)
• The change in temperature, ΔT = 90°C - 10°C = 80°C

Now, substitute these values into the formula:

q = (20,000 g)(0.450 J/g°C)(80°C) = 720,000 J

Therefore, the heat required is 720,000 Joules.