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3 bulbs each of resistance 8 Ohm are connected in series. The circuit has a voltage source of 12 volts. Find: 1) the total resistance of the circuit 2) the current flowing through each bulb

Choose all applying options.
a.I=0.5A
b.I=2A
c.Req=360
d.Req=240

User Keng
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1 Answer

1 vote

Final answer:

The total resistance (Req) in the series circuit is 24 Ohms, and the current (I) flowing through each bulb is 0.5A; thus, option (a) I=0.5A is correct, and the other given options are incorrect.

Step-by-step explanation:

Calculating Total Resistance and Current in a Series Circuit

When three bulbs, each with a resistance of 8 Ohms, are connected in series, the total resistance (Req) of the circuit is the sum of the individual resistances. This is found by the formula Req = R1 + R2 + R3. Therefore, Req equals to 24 Ohms (since 8 Ohm + 8 Ohm + 8 Ohm = 24 Ohm). To find the current (I) flowing through each bulb, Ohm's Law (I = V/R) is applied. With a voltage source (V) of 12 volts, the current would be I = 12 V / 24 Ohm, resulting in 0.5A.

Accordingly, the correct answers to the student's question are:

Req = 24 Ohms, which is not among the given options.

I = 0.5A, which corresponds to option (a).

Neither option (b) nor the incorrect values for Req (options c and d) apply in this case.

User Bilal Khan
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