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A freezer has a coefficient of performance 2.40, the freezer is to convert 1.80kg of water at 25°c to 1.8 of ice -5°c in one hour.What amount of heat must be removed from the water at 25°c to convert it to ice at -5°c?. How much electrical energy is consumed by the freezer during this hour ?. How much wasted heat is delivered to the room in which the freezer sits?​

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Final answer:

To determine the amount of heat removed from the water to convert it to ice, use the specific heat formula. Use the formula for coefficient of performance to calculate the electrical energy consumed by the freezer. To determine the wasted heat delivered to the room, subtract the heat consumed by the freezer from the heat removed.

Step-by-step explanation:

To determine the amount of heat that must be removed from the water to convert it to ice, we need to use the specific heat formula. The specific heat of ice is 2.09 J/g°C and the specific heat of water is 4.18 J/g°C. First, calculate the heat required to cool the water from 25°C to 0°C using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature. Then, calculate the heat required to freeze the water from 0°C to -5°C using the same formula. The total heat required is the sum of these two calculations.

To determine the electrical energy consumed by the freezer, we can use the formula electrical energy = power × time. We are given the coefficient of performance, which is the ratio of heat removed to work input. The formula for coefficient of performance (COP) is COP = heat removed / work input. Rearranging the formula, we can solve for work input as work input = heat removed / COP. Use this formula to calculate the work input, and then use it along with the given time to calculate the electrical energy consumed.

To determine the wasted heat delivered to the room, we need to subtract the heat removed from the heat consumed. The wasted heat is the heat removed minus the heat consumed by the freezer.

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