Final answer:
To calculate the grams of hydrogen in the 2.00 L sample of wet gas, we need to consider the water vapor present in the sample. The wet gas sample contains 0.30 L of water vapor, and the mass of the hydrogen in the sample is 1.758 grams.
Step-by-step explanation:
To calculate the grams of hydrogen in the 2.00 L sample of wet gas, we need to consider the water vapor present in the sample. From the given examples, we know that in a certain experiment, a volume of 2.58 L of hydrogen gas was collected over water. The volume that the dry hydrogen would occupy at STP (Standard Temperature and Pressure) was found to be 2.28 L. This means that the wet gas sample contains 0.30 L of water vapor.
Since the density of water vapor at STP is 0.8064 g/L, the mass of the water vapor in the sample is (0.8064 g/L) * (0.3 L) = 0.242 g. Therefore, the remaining mass in the sample is due to hydrogen, which is 2.00 g - 0.242 g = 1.758 g. Thus, there are 1.758 grams of hydrogen in the 2.00 L sample of wet gas.