Question

A local company wants to evaluate their quality of service by surveying their customers. Their budget limits the number of surveys to 250. What is their maximum error of the estimated mean quality for a 95% level of confidence and an estimated standard deviation of

a.112
b.2.72
c.119
d.1.3404
e.1.36

Answer 1

To find the maximum error of the estimated mean quality, use the formula Error = Z-score * (Standard Deviation / Square Root of Sample Size). For a 95% level of confidence, the Z-score is 1.96.

Step-by-step explanation:

To determine the maximum error of the estimated mean quality, we can use the formula: Error = Z-score * (Standard Deviation / Square Root of Sample Size). For a 95% level of confidence, the Z-score is 1.96. Using the estimated standard deviation values, we can calculate the maximum errors as follows:

1. a.112: Error = 1.96 * (0.112 / Square Root of 250) = 0.0168
2. b.2.72: Error = 1.96 * (2.72 / Square Root of 250) = 0.4042
3. c.119: Error = 1.96 * (119 / Square Root of 250) = 7.3433
4. d.1.3404: Error = 1.96 * (1.3404 / Square Root of 250) = 0.1992
5. e.1.36: Error = 1.96 * (1.36 / Square Root of 250) = 0.2026

Therefore, the maximum errors for the estimated mean quality are:

• a.112: 0.0168
• b.2.72: 0.4042
• c.119: 7.3433
• d.1.3404: 0.1992
• e.1.36: 0.2026