Question

11. 9 Reason Abstractly Explain why astudent who runs 3/4 mile in 6 minutes isfaster than a student who runs 1/2 mile in5 minutes.

Answer 1

hello

to solve this question, need to calculate their speeds and compare

student A ran 3/4 miles in 6 mins

`\text{speed}=(dis\tan ce)/(time)`

now we can substitute the values into the equatio