Final answer:
To calculate the force exerted by block B when it is lifted along with block A, we determine the total weight of both blocks and add the force applied. With the total mass at 0.4 kg, the force exerted by block B when lifted is 8.924 N.
Step-by-step explanation:
The question involves calculating the force exerted by block B (mass of 300 grams) when block A (mass of 100 grams) is placed on top and block B is pushed vertically upward with a force of 5 N. To determine this force, we can use Newton's second law of motion, F=ma, where F is the force applied, m is the total mass being accelerated, and a is the acceleration.
First, we convert the masses into kilograms:
- Mass of block A = 100 grams = 0.1 kg
- Mass of block B = 300 grams = 0.3 kg
Next, we calculate the total mass:
Total mass (m) = mass of block A + mass of block B = 0.1 kg + 0.3 kg = 0.4 kg
Using the force (F) of 5 N that is applied:
F = ma
Now we can solve for the acceleration (a):
a = F/m = 5 N / 0.4 kg = 12.5 m/s^2
Finally, we find the total force exerted by block B when lifted, which includes the weight of both blocks (gravity force) and the applied force:
Total force = weight of block A + weight of block B + applied force
Weight of block A = mass of block A × gravity = 0.1 kg × 9.81 m/s^2 = 0.981 N
Weight of block B = mass of block B × gravity = 0.3 kg × 9.81 m/s^2 = 2.943 N
Total force exerted by block B = 0.981 N + 2.943 N + 5 N = 8.924 N