Question

Consider reaction C + O2 =CO2 A reaction mixture contains 61 g of C and 61 g of O2. Calculate the theoretical yield of CO2.

Answer 1

The theoretical yield of CO2, given 61 g of C and 61 g of O2, is calculated by finding the limiting reactant and converting its moles to grams of CO2. Oxygen is the limiting reactant, and the theoretical yield of CO2 is 84.1 g.

Step-by-step explanation:

To calculate the theoretical yield of CO2 from the reaction C + O2 = CO2, we must first find the limiting reactant. We start by converting the mass of each reactant to moles.

Atomic mass of C (carbon) = 12.01 g/mol
Molecular mass of O2 (oxygen) = 32.00 g/mol

For carbon:
61 g C * (1 mol C / 12.01 g C) = 5.08 mol C

For oxygen:
61 g O2 * (1 mol O2 / 32.00 g O2) = 1.91 mol O2

The stoichiometry of the reaction requires 1 mole of O2 for every 1 mole of C to produce CO2.

Since we have more moles of C than O2, O2 is the limiting reactant.

Now, we use the moles of O2 to find the mass of CO2 produced:
1.91 mol O2 * (1 mol CO2 / 1 mol O2) * (44.01 g CO2 / 1 mol CO2)= 84.1 g CO2

Therefore, the theoretical yield of CO2 is 84.1 g.