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A block of wood is move 30cm along a rough surface. If the mass of the wood is 25kg and the coefficient of friction is 0.8. What is the minimum work done?

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Final answer:

The minimum work done by the force of friction is 58.8 J.

Step-by-step explanation:

To find the minimum work done, we need to calculate the force of friction first. The force of friction can be found using the formula F_friction = coefficient of friction × normal force. In this case, the normal force is equal to the weight of the block, which is given by W = mass × gravity.

So, W = 25 kg × 9.8 m/s² = 245 N. The force of friction is then F_friction = 0.8 × 245 N = 196 N.

The work done by the force of friction can be calculated using the formula Work = force × distance. In this case, the distance is given as 30 cm, which is equal to 0.3 m. So, the work done by the force of friction is Work = 196 N × 0.3 m = 58.8 J.

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