Final answer:
In projectile motion, an object thrown downward with an initial velocity of 30 m/s from a height of 200 m will travel approximately 292.5 meters downward in 5 seconds.
Step-by-step explanation:
In projectile motion, the distance traveled by an object thrown downward can be determined using the equations of motion. The equation for the distance traveled (d) is given by:
d = initial velocity * time + 0.5 * acceleration * time^2
In this case, the object is thrown downward with an initial velocity of 30 m/s from a height of 200 m. Since the object is thrown downward, the initial velocity is negative (-30 m/s). The acceleration due to gravity is -9.8 m/s^2.
Calculate the time (t) it takes for the object to reach the ground using the equation:
0 = -200 + (-30)t + 0.5 * (-9.8) * t^2
This is a quadratic equation that can be solved to find t. In this case, t is approximately 5.2 seconds.
Calculate the distance traveled (d) using the equation:
d = -30 * 5 + 0.5 * (-9.8) * 5^2
d is approximately -292.5 meters, which means the object will travel approximately 292.5 meters downward in 5 seconds.