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Is there a value of k for which the equation 2(kx + 2) + 9 = 4(x + k) + 1 has infinitely many solutions? Explain.

User Jalsh
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1 Answer

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Final answer:

The value of k for which the equation has infinitely many solutions is -2.

Step-by-step explanation:

To find a value of k for which the equation has infinitely many solutions, we need to find the condition where the equation simplifies to a tautology, such as 0 = 0. Let's solve the equation step by step:

2(kx + 2) + 9 = 4(x + k) + 1

2kx + 4 + 9 = 4x + 4k + 1

2kx + 13 = 4x + 4k + 1

2kx - 4x + 13 = 4k + 1

(2k - 4)x + 13 = 4k + 1

Here, x is a variable and k is a constant. For there to be infinitely many solutions, the coefficient of x on the left side of the equation should be equal to the coefficient of x on the right side of the equation, and the constants on both sides should be equal. Let's set up the equation:

2k - 4 = 4k

Solving for k:

2k - 4k = 4

-2k = 4

k = -2

Therefore, the value of k for which the equation has infinitely many solutions is -2.

User Gluecks
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