Final answer:
The real zeros of the polynomial function h(t) = t²-4t+4 are t = 2.
Step-by-step explanation:
The polynomial function h(t) = t²-4t+4 is a quadratic equation of the form at² + bt + c = 0, with constants a = 1, b = -4, and c = 4. To find the real zeros, we can use the quadratic formula. Plugging in the values, we get:
t = (-b ± √(b² - 4ac)) / (2a)
Substituting the values, we have:
t = (-(-4) ± √((-4)² - 4(1)(4))) / (2(1))
t = (4 ± √(16 - 16)) / 2
t = (4 ± √0) / 2
t = (4 ± 0) / 2
t = 4 / 2
t = 2
Therefore, the real zeros of the polynomial function h(t) = t²-4t+4 are t = 2.