Question

For the reaction: H₂(g) + Cl₂(g) → 2HCl(g), how many moles of HCl will be produced from 10.0 g of H₂?

A. 2 mole
B. 5 mole
C. 10 mole
D. 20 mole

Answer 1

Approximately 10 moles of HCl will be produced from 10.0 g of H₂ based on the balanced chemical equation H₂(g) + Cl₂(g) → 2HCl(g), and the molar mass of H₂, which is 2.016 g/mol.

Step-by-step explanation:

To determine how many moles of HCl will be produced from 10.0 g of H₂, we need to follow these steps:

1. Calculate the molar mass of H₂.
2. Convert the mass of H₂ to moles using the molar mass.
3. Use the stoichiometry of the balanced equation to find the moles of HCl produced.

The molar mass of H₂ is approximately 2.016 g/mol. So, 10.0 g of H₂ is:

10.0 g H₂ * (1 mol H₂ / 2.016 g H₂) = 4.9603 mol H₂

The balanced chemical equation, H₂(g) + Cl₂(g) → 2HCl(g), tells us that 1 mole of H₂ produces 2 moles of HCl. Therefore, the moles of HCl produced from 4.9603 mol of H₂ is:

4.9603 mol H₂ * (2 mol HCl / 1 mol H₂) = 9.9206 mol HCl

Rounding to the nearest whole number, as the answer choices are in whole numbers, we get approximately 10 moles of HCl. Therefore, option C is correct.