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Find the slopes of the sides of square ABCD, given vertices at A(-2,5) and B(4,3), with the slope of -1/3.

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Final answer:

The slopes of the sides of square ABCD are -1/3.

Step-by-step explanation:

To find the slopes of the sides of square ABCD, we can use the formula for slope, which is m = (y2 - y1)/(x2 - x1). Given the vertices at A(-2,5) and B(4,3), we can calculate the slope of AB as follows:

  1. Let (x1, y1) = (-2, 5) and (x2, y2) = (4, 3).
  2. Substituting the values into the slope formula, we get m = (3 - 5)/(4 - (-2)).
  3. Simplifying the expression, we have m = -2/6.
  4. Therefore, the slope of AB is -1/3.

Similarly, since ABCD is a square, we know that all the sides have the same slope of -1/3.

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