Final answer:
The magnetic force acting on a straight wire carrying a current in a perpendicular magnetic field is calculated with the formula F = I * L * B * sin(90°), resulting in a force of 0.04 Newtons for the given parameters.
Step-by-step explanation:
The subject of the question is physics, specifically the interaction between electric currents and magnetic fields, and the forces generated as a result. This falls under the concept of electromagnetism, which is typically a part of a high school physics curriculum.
To find the magnetic force acting on a straight wire carrying a current placed in a uniform magnetic field, we use the formula F = I * L * B * sin(θ), where:
- I represent the current in the wire (2A in this instance)
- L represents the length of the wire in the field (1.00m or 100cm)
- B represents the magnetic field's strength (0.02T)
- θ is the angle between the current direction and the magnetic field direction
Since the wire is along the X-axis and the magnetic field is along the Y-axis, they are perpendicular to each other, which means that θ = 90° and sin(90°) = 1. The force can be calculated as follows:
F = I * L * B * sin(90°)
F = 2A * 1.00m * 0.02T *1
F = 0.04N
Thus, the magnetic force acting on the wire is 0.04 Newtons.