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A straight wire 100 cm long along the X axis has a current of 2A. Find the magnetic force acting on this piece of wire in a uniform magnetic field of

0.02T along the y-axis.

User David Rojo
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Final answer:

The magnetic force acting on a straight wire carrying a current in a perpendicular magnetic field is calculated with the formula F = I * L * B * sin(90°), resulting in a force of 0.04 Newtons for the given parameters.

Step-by-step explanation:

The subject of the question is physics, specifically the interaction between electric currents and magnetic fields, and the forces generated as a result. This falls under the concept of electromagnetism, which is typically a part of a high school physics curriculum.

To find the magnetic force acting on a straight wire carrying a current placed in a uniform magnetic field, we use the formula F = I * L * B * sin(θ), where:

  • I represent the current in the wire (2A in this instance)
  • L represents the length of the wire in the field (1.00m or 100cm)
  • B represents the magnetic field's strength (0.02T)
  • θ is the angle between the current direction and the magnetic field direction

Since the wire is along the X-axis and the magnetic field is along the Y-axis, they are perpendicular to each other, which means that θ = 90° and sin(90°) = 1. The force can be calculated as follows:

F = I * L * B * sin(90°)

F = 2A * 1.00m * 0.02T *1

F = 0.04N

Thus, the magnetic force acting on the wire is 0.04 Newtons.

User Jimmu
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