Question

If 76% of female prison inmates are mothers and 2 female prison inmates are selected at random, what is the probability that none are mothers? (Rounded to three decimal places if necessary.)

Answer 1

To find the probability that neither of the two randomly selected female prison inmates are mothers, we multiply the probability of one such inmate not being a mother (24%) by itself, resulting in a probability of 0.058.

Step-by-step explanation:

The question asks about the probability that two female prison inmates selected at random are not mothers, given that 76% of female prison inmates are mothers. To find the probability of selecting an inmate who is not a mother, we subtract 76% from 100% to get 24%. This represents the likelihood of one random inmate not being a mother, as a decimal this is 0.24. Therefore, the probability that both inmates selected are not mothers is found by multiplying the individual probabilities together: 0.24 × 0.24, which is equal to 0.0576. Rounded to three decimal places, this gives us a probability of 0.058.