Final answer:
The area of the larger square is four times larger than the area of the smaller square. To compare them, we calculate the area of both squares, with the larger square having a side length that is twice that of the smaller square, resulting in a ratio of 4:1.
Step-by-step explanation:
Marta has a square with a side length of 4 inches. If the dimensions of a similar square are twice that of the first square, then the side length of the larger square would be 8 inches. To understand how the area of the larger square compares to the area of the smaller square, we should first calculate the areas of both squares.
The area of the smaller square is 4 inches × 4 inches = 16 square inches. The area of the larger square is 8 inches × 8 inches = 64 square inches. Now, to compare the two areas, we write a ratio, which is 64 square inches to 16 square inches, simplifying down to 4:1. This means the area of the larger square is four times larger than the area of the smaller square.