Question

A falling rock is viewed to pass by a window that has a height of 2.2 m in 0.40 s

a. Find the V of the rock as it reaches the bottom of the window

Answer 1

The velocity of the falling rock as it reaches the bottom of the window is 5.5 m/s.

Step-by-step explanation:

The velocity of the falling rock as it reaches the bottom of the window can be calculated using the formula:

V = Δy / t

Where V is the velocity, Δy is the change in height, and t is the time taken. In this case, the change in height is 2.2 m and the time taken is 0.40 s. Substituting these values into the formula, we get:

V = 2.2 m / 0.40 s = 5.5 m/s

Therefore, the velocity of the rock as it reaches the bottom of the window is 5.5 m/s.