Question

Accessibility ModePrintFindPart II: Limiting Reactant1. Consider the reaction: 5C +2SO₂ → CS₂ + 4COa.) If you had 10 mol of Carbon, how many moles of carbon monoxide would be produced?b.) If you had 10 mol of sulfur dioxide, how many moles of carbon monoxide would beproduced?c.) If you had 10 mol of C and SO2 which reactant would be limiting?d.) What is the theoretical yield of CO, in moles if you react 10 moles of each reactant?SAMEFaPmenSavarہےEP Immersive Reader

Answer 1

a.) 8 moles of carbon monoxide (CO).

b.) 20 moles of carbon monoxide (CO)

c.) C is the limiting reactant.

d.) The theoretical yield of CO would be 8 moles.

Step-by-step explanation:

Let's write the chemical equation:

`5C+2SO_2\rightarrow CS_2+4CO.`

a.) You can see that 5 moles of carbon (C) reacted produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient in the chemical equation by 2 (because we will have 10 moles of carbon):

The answer is that we will produce 8 moles of carbon monoxide (CO) by 10 moles of carbon (C).

b.) We can apply the same logic to this case. In the chemical equation, we have 2 moles of sulfur dioxide (SO2) reacted that produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient by 5 so we will have 10 moles of sulfur dioxide:

The answer is that we will produce 20 moles of carbon monoxide (CO) by 10 moles of sulfur dioxide (SO2).

c.) We have already known that 10 moles of C will produce 8 moles of CO, and 10 moles of SO2 will produce 20 moles of CO. If we react 10 moles of C and 10 moles of SO2, you can note that we're going to have an excess of SO2 because we don't have enough amount of C to produce 20 moles of CO as SO2 do. So based on this logic, C is being consumed first and C would be the limiting reactant.

d.) Remember that the theoretical yield indicates the amount of a product obtained in a chemical reaction.

As we saw before, C is the limiting reactant if we react 10 moles of each reactant, so we have already known that 10 moles of C reacted produces 8 moles of CO, so the theoretical yield of CO would be 8 moles.