Final answer:
To find the total time in the air for a pomegranate thrown up 1m and falling back to the same position, we use kinematic equations, resulting in approximately 0.9032 seconds.
Step-by-step explanation:
To determine the total time in the air for a pomegranate thrown vertically, we can use the principles of kinematics in projectile motion neglecting air resistance. The time taken to rise to the peak is the same as the time taken to fall back down to the same level, assuming no air resistance. We can use the formula t = √(2h / g), where t is the time to reach the peak, h is the height (1 meter in this case), and g is the acceleration due to gravity (approximately 9.8 m/s²). Solving for t, we get t = √(2 * 1 m / 9.8 m/s²) = √(0.2041) ≈ 0.4516 seconds. To get the total time, we double this value (one ascent plus one descent), resulting in approximately 0.9032 seconds in total.