Final answer:
The final volume of the balloon would be approximately 2215.43 mL when it drifts into an airlock where the temperature is -95°C and the pressure is 0.115 atm, as calculated using the combined gas law.
Step-by-step explanation:
The final volume of a balloon drifting into an airlock with a temperature of -95°C and pressure of 0.115 atm can be determined using the combined gas law which states that the ratio of the product of pressure and volume to temperature is a constant for a given amount of gas when moles remain constant (P1V1/T1 = P2V2/T2). To find the final volume (V2), we rearrange the combined gas law to V2 = P1V1T2 / (P2T1). Given that the initial volume (V1) is 425 mL, initial pressure (P1) is not provided but it can be assumed standard pressure (1 atm), initial temperature (T1) and final temperature (T2) must be converted to Kelvin.
Converting temperatures to Kelvin:
T1 = 25°C + 273.15 = 298.15 KT2 = -95°C + 273.15 = 178.15 K
Now let's plugin the values into the equation:
V2 = (1 atm × 425 mL × 178.15 K) / (0.115 atm × 298.15 K)
Perform the calculation:
V2 = (425 × 178.15) / (0.115 × 298.15)
V2 = 75935.75 / 34.28725
V2 ≈ 2215.43 mL
The final volume of the highly elastic balloon at -95°C and 0.115 atm pressure would be approximately 2215.43 mL, assuming the temperature and amount of gas in the balloon remain constant.