54.6k views
1 vote
Which of these relations is NOT a function?"

A. R = {(0, 0), (2, 6), (-4, -12), (-5, -15)}
B. R = {(-2, 2), (2, -2), (-4, 4), (4, -4)}
C. R = {(4, 5), (4, 8), (5, 10), (6, 12)}
D. R = {(2, 3), (4, 3), (6, 3), (5, 3)}

User Iam Zesh
by
8.3k points

1 Answer

7 votes

Final answer:

Option C, R = {(4, 5), (4, 8), (5, 10), (6, 12)}, is NOT a function because it has the same x-value (4) mapping to two different y-values (5 and 8), violating the definition of a function.

Step-by-step explanation:

To determine which of these relations is NOT a function, we need to remember that in a function, each input value should map to exactly one output value. That means, that for each x-value, there should be only one corresponding y-value.

  • Option A: The set R = {(0, 0), (2, 6), (-4, -12), (-5, -15)} maps unique x-values to unique y-values, so it is a function.
  • Option B: The set R = {(-2, 2), (2, -2), (-4, 4), (4, -4)} also shows a one-to-one relationship between x and y-values, and is a function.
  • Option C: The set R = {(4, 5), (4, 8), (5, 10), (6, 12)} has the x-value 4 mapping to two different y-values, 5 and 8, which means it is NOT a function.
  • Option D: The set R = {(2, 3), (4, 3), (6, 3), (5, 3)} has different x-values mapping to the same y-value, which is acceptable in a function.

Therefore, the relation that is NOT a function is Option C.

User Jeremy Ferguson
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories