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A fisherman leaves his home port and heads in the direction N 70°W. He travels 30 miles. How far north and how far west is he from his home port?

User Ibarrond
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Final answer:

To determine the distance north and west a fisherman is from his home port, trigonometry is used to calculate the sides of a right triangle formed by his travel path. The fisherman is approximately 10.26 miles west and 28.68 miles north from his starting point.

Step-by-step explanation:

The student has asked to determine how far north and how far west a fisherman is from his home port after traveling 30 miles in the direction N 70°W. To solve this, we can decompose the fisherman's travel into a right triangle where the fisherman's path is the hypotenuse. Using trigonometry, the fisherman's travel west (x) can be described as x = 30 × {\sin(70°)} and the travel north (y) as y = 30 × {\cos(70°)}. By calculating these, we find that:

Travel to the west (x) ≈ 10.26 milesTravel to the north (y) ≈ 28.68 miles

Hence, the fisherman is approximately 10.26 miles west and 28.68 miles north from his home port after his journey.

User Pedromtavares
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