Question

Consider Fe2(SO4)3 + 6 H2O+ 6NH3 → 2Fe(OH)3 + 3(NH4)2SO4 Calculate the mass of water required to make 3.67 g Fe(OH)3

Answer 1

To calculate the mass of water required to make 3.67 g Fe(OH)3, we need to consider the balanced chemical equation and use molar ratios.

Step-by-step explanation:

To calculate the mass of water required to make 3.67 g Fe(OH)3, we need to use the balanced chemical equation:

Fe2(SO4)3 + 6 H2O+ 6 NH3 → 2 Fe(OH)3 + 3(NH4)2SO4

From the equation, we can see that 6 moles of water react to form 2 moles of Fe(OH)3.

To calculate the mass of water, we use the molar mass of water (18.015 g/mol):

1. Calculate the molar mass of Fe(OH)3:

• 1 Fe atom: 55.845 g/mol
• 3 O atoms: 3 x 16.00 g/mol
• 3 H atoms: 3 x 1.008 g/mol

Add the masses of each element to get the molar mass of Fe(OH)3.Convert the given mass of Fe(OH)3 to moles.Use the molar ratio from the balanced equation to calculate the moles of water required.Convert the moles of water to grams by multiplying by the molar mass of water.