Final answer:
The z-score calculation for the hypothesis test shows that we cannot conclusively reject the claim that the mean SATM score is no more than 473 for all California seniors at the 95% confidence level. However, our sample has a higher mean, indicating the claim might not be accurate.
Step-by-step explanation:
To evaluate the claim about SAT Mathematics (SATM) scores, we use a hypothesis test to determine whether the sample mean score of 485 differs significantly from the hypothesized population mean score of 473. Given a standard deviation of 95 and a sample size of 450, we calculate the z-score.
The z-score is given by the formula:
z = (sample mean - hypothesized mean) / (standard deviation / sqrt(sample size))
z = (485 - 473) / (95 / sqrt(450)) ≈ 1.78
A z-score of 1.78 is less than the critical value of 1.96 for a 95% confidence level (two-tailed test). Therefore, we do not have enough evidence to reject the claim that the true mean score is no more than 473 at the 95% level. However, the sample mean is higher than 473, which suggests that the claim may not represent the true SATM abilities of the population of California high school seniors.