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Using the falling object distance formula d = 2 + 16t^2, calculate how long it will take for the object to travel 68 feet.

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Final answer:

The object will take approximately 2.03 seconds to travel 68 feet, as calculated by setting the falling distance to 68 in the formula and solving for time.

Step-by-step explanation:

To calculate how long it will take for the object to travel 68 feet using the falling object distance formula d = 2 + 16t^2, we first need to set up the equation with the given distance:

68 = 2 + 16t^2

Subtract 2 from both sides of the equation:

66 = 16t^2

Divide both sides by 16 to solve for t^2:

t^2 = 66 / 16

t^2 = 4.125

Take the square root of both sides to solve for t:

t = sqrt(4.125)

t ≈ 2.03 seconds

Therefore, it will take approximately 2.03 seconds for the object to travel 68 feet.

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