Final answer:
a) 1.0 electron volt (eV) is equal to 1.60 × 10^(-19) joules (J). b) The speed of a proton with 5000 eV of kinetic energy is approximately 1.19 × 10^7 m/s.
Step-by-step explanation:
a) To convert 1 electron volt (eV) to joules (J), we can use the conversion factor 1 eV = 1.60 × 10-19 J (as given in the reference information). Therefore, 1.0 eV is equal to 1.60 × 10-19 J.
b) The kinetic energy of a proton with 5000 eV can be calculated using the equation E = 0.5mv2, where E is the kinetic energy, m is the mass of the proton, and v is its velocity. Since we are given the energy in eV, we need to convert it to joules before proceeding. Using the conversion factor 1 eV = 1.60 × 10-19 J, we can convert 5000 eV to 8.00 × 10-17 J. Now we can plug this value into the equation along with the mass of a proton (1.67 × 10-27 kg) to find the velocity of the proton. Solving for v, we get v = √(2E/m) = √(2(8.00 × 10-17 J)/(1.67 × 10-27 kg)) ≈ 1.19 × 107 m/s.