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Equation in standard form of a parabola with x-intercepts at (7,0) and (10,0) that opens upward.

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Final answer:

The equation in standard form of a parabola with x-intercepts at (7,0) and (10,0) that opens upward is y = a(x - 7)(x - 10)

Step-by-step explanation:

The equation in standard form of a parabola with x-intercepts at (7,0) and (10,0) that opens upward can be written as:

y = a(x - 7)(x - 10)

Since the parabola opens upward, the coefficient 'a' must be positive. To determine the value of 'a', we can substitute one of the given points into the equation:

0 = a(7 - 7)(7 - 10)

0 = a(0)(-3)

0 = 0

This equation holds true for any value of 'a', which means there are infinitely many parabolas that satisfy the given conditions. Therefore, the standard form of the equation of a parabola with x-intercepts at (7,0) and (10,0) that opens upward is y = a(x - 7)(x - 10)

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