Question

Aniline is a weak organic base with the formular C6H5NH2. The anilinium ion has the formulaC6H5NH3+ and its Ka = 0.000023. a) write the chemical reaction showing the hydrolysis of the anilinium ion. b) calculate the PH of a 0.0400M solution of anilinium chloride.

Answer 1

The hydrolysis of the anilinium ion (C6H5NH3+) in water forms H3O+ and C6H5NH2. To calculate the pH of a 0.0400M anilinium chloride solution, use the ICE table with the given Ka value, then find the concentration of H3O+ and convert to pH.

Step-by-step explanation:

Hydrolysis of the Anilinium Ion and pH Calculation

The hydrolysis of the anilinium ion C6H5NH3+ can be represented by the following chemical reaction:

C6H5NH3+ (aq) + H2O(l) ⇌ H3O+ (aq) + C6H5NH2 (aq)

To calculate the pH of a 0.0400M anilinium chloride solution, we use the known value of Ka = 2.3 × 10⁻⁵. Assuming that the degree of hydrolysis is small, we can set up an ICE table and solve for the concentration of H3O+. The pH is then calculated as the negative logarithm of the H3O+ concentration.

pH Calculation Steps

1. Write the hydrolysis equation and expression for Ka.
2. Set up an ICE table for the equilibrium concentrations.
3. Solve for [H3O+] and use pH = -log[H3O+].

By following these steps with the given solution concentration and Ka, you can determine the pH of the anilinium chloride solution.