Question

How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7 g Fe? Equation Fe2O2(g) + 3CO(g) -> 3CO2(g) + 2Fe(g)

Answer 1

Answer: 157.3 g CO

Step-by-step explanation:

Fe2O3 + 3CO —> 3CO2 + 2Fe [1 mol + 3 mol —> 3 mol + 2 mol]

3 mol CO —> 2 mol Fe

3*28g —> 2*56g

amt CO 3*28*209.7/(2*56) = 157.3g