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If 45.86 g Ca₅(PO₄)₃F is mixed with 83.43 g H₂SO₄, how much H₃PO₄ will form?

A) 26.74 g
B) 27.49 g
C) 48.64 g
D) 50.02 g

1 Answer

6 votes

Final answer:

To find out how much H₃PO₄ will form, we need to determine the limiting reactant in the reaction between Ca₅(PO₄)₃F and H₂SO₄. The limiting reactant is H₂SO₄ and the theoretical yield of H₃PO₄ is 27.49 g (Choice B).

Step-by-step explanation:

To find out how much H₃PO₄ will form, we need to determine the limiting reactant in the reaction between Ca₅(PO₄)₃F and H₂SO₄. First, convert the given masses of Ca₅(PO₄)₃F and H₂SO₄ to moles using their molar masses. Then, use the balanced chemical equation to determine the stoichiometric ratio between Ca₅(PO₄)₃F and H₃PO₄.

From the stoichiometric ratio, we can determine the theoretical yield of H₃PO₄. Finally, compare the theoretical yield with the actual yield of H₂SO₄ to identify the limiting reactant. The amount of H₃PO₄ that forms will be equal to the amount produced by the limiting reactant.

In this case, the limiting reactant is H₂SO₄ and the theoretical yield of H₃PO₄ is 27.49 g (Choice B).

User Keithwyland
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