Final answer:
Using Charles's Law, the temperature at which a gas that occupies 2.6 L at 25°C would occupy 3 L is approximately 70.5°C. The calculation involves converting Celsius to Kelvin, rearranging the Charles's Law equation, and solving for the final temperature.
Step-by-step explanation:
To determine the temperature at which a gas that occupies 2.6 L at 25°C would occupy a volume of 3 L, you can use Charles's Law. Charles's Law states that for a given amount of gas at constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin (V/T = constant). Therefore, we can set up the equation V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature we want to find.
First, we will convert the initial temperature from °C to Kelvin by adding 273.15: T1 = 25°C + 273.15 = 298.15 K. Then we can rearrange the Charles's Law equation to solve for T2: T2 = (V2 × T1) / V1.
Plugging in the known values, we get T2 = (3 L × 298.15 K) / 2.6 L = 343.65 K. Finally, to convert this back to °C, we subtract 273.15: T2 = 343.65 K - 273.15 = 70.5°C
So, the gas would occupy 3 L at a temperature of approximately 70.5°C, assuming constant pressure.