Question

A circuit contains three capacitors connected in parallel. If the capacitors are rated at 0.01 F, 0.002 F, and 0.6F, what is the circuit's total capacitance

A.0.216 F
B. 0.006 F
C. 0.612 F
D.0.082 F

Answer 1

The total capacitance of the parallel circuit with capacitors rated at 0.01 F, 0.002 F, and 0.6 F is 0.612 F.

Step-by-step explanation:

The total capacitance of a circuit containing three capacitors connected in parallel can be found by simply adding the capacitances of the individual capacitors together. The capacitors in the student's question have capacitances of 0.01 F, 0.002 F, and 0.6 F. Therefore, the circuit's total capacitance (CT) is equal to the sum of these values:

CT = 0.01 F + 0.002 F + 0.6 F = 0.612 F.

The correct answer to the question is C. 0.612 F.