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N(n+1)+(n+2)=-20-4. What are the three consecutive integers?

User Bkkbrad
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Final answer:

The equation provided does not yield real-number solutions for n, therefore, there are no three consecutive integers that satisfy the given equation.

Step-by-step explanation:

The question is asking to find three consecutive integers that satisfy a given equation. The equation provided can be simplified as follows:

n(n+1)+(n+2)=-20-4 simplifies to n^2 + n + n + 2 = -24, which further simplifies to n^2 + 2n + 2 = -24. To solve for n, we can move all terms to one side to get n^2 + 2n + 26 = 0.

However, after simplifying, we notice that the equation n^2 + 2n + 26 = 0 does not have real solutions because the discriminant (b^2 - 4ac) is negative, and therefore the equation has no real-number solutions. Thus, there are no three consecutive integers that satisfy the equation as stated.

User Poshest
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