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The chess club spent $138.52 on juice boxes, $75 on lemonade, and purchased three cases of water at $6.80 each. What is the total cost of the three cases of water?

User Jsonras
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1 Answer

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Final answer:

The total cost for three cases of water, with each case priced at $6.80, is $20.40 after multiplication.

Step-by-step explanation:

The total cost of the three cases of water can be found by multiplying the price per case by the number of cases. The price per case of water is $6.80, and the student purchases three cases.

  • Price per case: $6.80
  • Number of cases: 3

We calculate the total cost by multiplying the two:

Total cost = Price per case × Number of cases

Total cost = $6.80 × 3

Total cost = $20.40

Therefore, the total cost of the three cases of water is $20.40.

User Nndru
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