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What is the solute potential of 0.2M marshmallow placed in an open container of cocoa measuring 80°C? (i = 1)​

User Jarlax
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Final answer:

The solute potential of a solution can be calculated using the formula: Ψs = -iCRT. The solute potential of the 0.2 M marshmallow solution at 80°C is -5.83 atm.

Step-by-step explanation:

The solute potential of a solution can be calculated using the formula: Ψs = -iCRT, where Ψs is the solute potential, i is the ionization constant (which is 1 for marshmallow), C is the molar concentration of the solution in mol/L, R is the ideal gas constant (≈ 0.0821 L atm/mol K), and T is the absolute temperature in Kelvin.

Given that the concentration of the marshmallow solution is 0.2 M and the temperature is 80°C (which is 353 K), we can calculate the solute potential as follows:

Ψs = -1 x (0.2 mol/L) x (0.0821 L atm/mol K) x (353 K) = -5.83 atm

So, the solute potential of the 0.2 M marshmallow solution at 80°C is -5.83 atm.

User Smoothumut
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