Question

A certain brand of antacid was analyzed by a student who used 50.00 mL of 0.4897M HCl to dissolve the tablet. The HCl remaining after the reaction required 8.85 mL of 1.299M NaOH to back-titrate.How many moles of HCI did the tablet neutralize?

Select one:
A. 0.4897 mol
B. 0.02449 mol
C. 0.01150 mol
D. 0.01299 mol

Answer 1

The moles of HCl neutralized by the antacid tablet is 0.01150 mol.

Step-by-step explanation:

To calculate the moles of HCl neutralized by the antacid tablet, we can use the back titration method.

First, calculate the moles of NaOH used in the back titration:

Moles of NaOH = Volume of NaOH (in L) x Concentration of NaOH (in M)

Moles of NaOH = 8.85 mL x 0.001299 M = 0.01147365 mol NaOH

Since the balanced equation between HCl and NaOH is 1:1, the moles of HCl neutralized by the tablet is also 0.01147365 mol.