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Find the equation of a line that is parallel to the line y = -8x - 6 and crosses the y-axis at (0,7).

User Nhtrnm
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Final answer:

To find the equation of a line parallel to y = -8x - 6 and crosses the y-axis at (0,7), use the slope-intercept form of a line and substitute the values.

Step-by-step explanation:

To find the equation of a line parallel to y = -8x - 6 and crosses the y-axis at (0,7), we know that parallel lines have the same slope. The given line has a slope of -8. So, the equation of the parallel line will also have a slope of -8. Now we can use the slope-intercept form of a line, y = mx + b, where m is the slope and b is the y-intercept. Since the line passes through the point (0,7), we can substitute these values into the equation.

So the equation of the line is y = -8x + 7.

User Joel Kandiah
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