Question

A bully is pushing a boy against a locker as shown with a force of 500N.The angle between his arms and the ground is 40°. Draw a free-body diagram of the boy and then find the normal force between the boy and the wall.

Answer 1

To find the normal force between the boy and the wall, we need to first draw a free-body diagram of the boy. The normal force is the force exerted by the wall on the boy and it acts perpendicular to the surface of the wall. The normal force can be found using the force components.

Step-by-step explanation:

To find the normal force between the boy and the wall, we need to first draw a free-body diagram of the boy. The force exerted by the bully pushing the boy against the locker is 500N at an angle of 40° with the ground. The normal force is the force exerted by the wall on the boy and it acts perpendicular to the surface of the wall. Since the boy is pushed against the wall, the normal force is equal in magnitude but opposite in direction to the force exerted by the bully.

Now, let's find the normal force using the force components. The vertical component of the force exerted by the bully is F_y = 500N * sin(40°).

Since the normal force is equal and opposite to the vertical component of the force exerted by the bully, the normal force is N = - F_y = -500N * sin(40°).

Therefore, the normal force between the boy and the wall is 500N * sin(40°).