Question

A cannonball is launched from the ground at an angle of 30 degrees above the horizontal and takes 4 seconds to reach the peak height. If the initial velocity is doubled, how much time will it take to reach the peak height?

Answer 1

When the initial velocity is doubled, it will take 2 seconds for the cannonball to reach the peak height.

Step-by-step explanation:

To find the time it will take for the cannonball to reach the peak height when the initial velocity is doubled, we need to understand the relationship between initial velocity and time of flight for a projectile.

The time of flight for a projectile launched at a certain angle above the horizontal is given by the equation:

T = (2 * V * sin(theta)) / g

Where T is the time of flight, V is the initial velocity, theta is the launch angle, and g is the acceleration due to gravity.

When we double the initial velocity, V, the time of flight, T, will be halved. Therefore, it will take 2 seconds for the cannonball to reach the peak height when the initial velocity is doubled.