Question

A chemist needs to mix 6 parts acid to 7 parts base for a reaction. If they need a total of 52mL (milliliters) of reaction, how many mL

of acid and base are needed?

Answer 1

24 millilitres acid

28 millilitres base

Explanation:

First, we need to know how many parts there are in total. We do this by adding the number of parts of acid (6) and base (7). 6+7=13

Then, divide 52 by 13 to find out how many millilitres makes up a part.

52/13=4

Then you multiply this by the number of parts for each substance.

4x6=24 millilitres acid

4x7=28 millitres base